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    <div class="moz-cite-prefix">Hi,<br>
      <br>
      I would suggest to use the Buckingham functionalilty, set C6 to
      zero and modify lines 957-959 of src/mdlib/tables.c to fill the
      table with your potential instead of exp(-a*r).<br>
      <br>
      Cheers,<br>
      <br>
      Berk<br>
      <br>
      On 10/17/2013 01:30 PM, Mark Abraham wrote:<br>
    </div>
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cite="mid:CAMNuMAS0DBWEAzLUUEuto+UiO=+UWc3syquS-iO1iTfuV3-ncg@mail.gmail.com"
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      <div dir="ltr">Hi,
        <div><br>
        </div>
        <div>It's hard to make any sense of the formatting of your
          equations, and you haven't said what over what quantity your A
          varies or what r and r* are... Do check out manual sections
          4.2.13 and 6.9.</div>
        <div><br>
        </div>
        <div>Mark</div>
      </div>
      <div class="gmail_extra"><br>
        <br>
        <div class="gmail_quote">On Tue, Oct 15, 2013 at 10:02 PM, Reza
          Ghafarian Shirazi <span dir="ltr">&lt;<a
              moz-do-not-send="true" href="mailto:rezagh@student.uef.fi"
              target="_blank">rezagh@student.uef.fi</a>&gt;</span>
          wrote:<br>
          <blockquote class="gmail_quote" style="margin:0 0 0
            .8ex;border-left:1px #ccc solid;padding-left:1ex">
            <div style="word-wrap:break-word">
              Dear all,
              <div><br>
              </div>
              <div>I'm trying to define modified morse potential in
                Gromacs to be used as a forcefield using tabulated
                potentials.</div>
              <div><br>
              </div>
              <div>My potential's functional form is as:&nbsp;<span
style="background-color:rgb(249,249,249);font-family:sans-serif;line-height:19px">&#949;
                  Exp[-2A(r-r*)] -2&nbsp;</span><span
style="background-color:rgb(249,249,249);font-family:sans-serif;line-height:19px">&#949;
                  Exp[-A(r-r*)]</span></div>
              <div><span
style="background-color:rgb(249,249,249);font-family:sans-serif;line-height:19px"><br>
                </span></div>
              <div><span style="background-color:rgb(249,249,249)"><font
                    face="sans-serif"><span style="line-height:19px">So
                      I have to define g&reg;&nbsp;=&nbsp;</span></font></span><span
style="background-color:rgb(249,249,249);font-family:sans-serif;line-height:19px">&#949;
                  Exp[</span><span
                  style="background-color:rgb(249,249,249)"><font
                    face="sans-serif"><span style="line-height:19px">-2A(r-r*)]
                      &nbsp;and h&reg;=</span></font></span><span
style="background-color:rgb(249,249,249);font-family:sans-serif;line-height:19px">-2&nbsp;</span><span
                  style="background-color:rgb(249,249,249)"><font
                    face="sans-serif"><span style="line-height:19px">&#949;
                      Exp[-A(r-r*)]. They have to be defined as
                      values&nbsp;in a&nbsp;xvg&nbsp;table where the table is filled
                      with values of r, f&reg;, f'&reg;, g&reg;,&#8230;.</span></font></span></div>
              <div><font face="sans-serif"><span
                    style="line-height:19px">My question is how can I
                    make vales of these&nbsp;functions, while there's a
                    variable in the exponential term.&nbsp;</span></font></div>
              <div><font face="sans-serif"><span
                    style="line-height:19px">I saw in the manual on the&nbsp;</span></font><a
                  moz-do-not-send="true"
href="http://www.gromacs.org/Documentation/How-tos/Tabulated_Potentials#Constructing_the_Table%28s%29"
                  target="_blank">website</a><font face="sans-serif"><span
                    style="line-height:19px">&nbsp;noting that h&reg;&nbsp;for
                    buckingham is expressed as h&reg;=AExp[-Br] so I was
                    wondering how they make the table of h&reg;&nbsp;values while
                    B is a variable.</span></font></div>
              <div><font face="sans-serif"><span
                    style="line-height:19px"><br>
                  </span></font></div>
              <div><font face="sans-serif"><span
                    style="line-height:19px">Solutions which cam&nbsp;ego&nbsp;my
                    mind were:</span></font></div>
              <div><font face="sans-serif"><span
                    style="line-height:19px">Should we use some&nbsp;</span></font><span
                  style="font-family:sans-serif;line-height:19px">mathematical
                  approximations like Exp[-u]=1-u.</span></div>
              <div><font face="sans-serif"><span
                    style="line-height:19px">or simply tabulated
                    potentials does not support potentials more complex
                    than lennard jones, and Buckingham is an integrated
                    feature which doesn't need the&nbsp;xvv&nbsp;table.</span></font></div>
              <div><font face="sans-serif"><span
                    style="line-height:19px">Any&nbsp;suggestions&nbsp;will be
                    appreciated</span></font></div>
              <div><font face="sans-serif"><span
                    style="line-height:19px"><br>
                  </span></font></div>
              <div><font face="sans-serif"><span
                    style="line-height:19px">regards</span></font></div>
              <span class="HOEnZb"><font color="#888888">
                  <div><font face="sans-serif"><span
                        style="line-height:19px">Reza&nbsp;</span></font></div>
                </font></span></div>
            <br>
            --<br>
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