Xi Zhao,<br><br>I have no script either. It's not my homework, and I'm not on your payroll. If I need a script like that and write it, I'll be happy to share it with you. But that's not going to be soon. At present, I don't even have a data set to use to develop something like it. On the other hand, if you put effort in writing a script for it (you may want to try and learn a bit of python), and get stuck, I'll be happy to reflect on your code, as will others that are on this list. That is how things work here.<br>
<br>Cheers,<br><br>Tsjerk<br><br><div class="gmail_quote">On Wed, Dec 23, 2009 at 2:07 AM, xi zhao <span dir="ltr"><<a href="mailto:zhaoxiitc2002@yahoo.com.cn">zhaoxiitc2002@yahoo.com.cn</a>></span> wrote:<br><blockquote class="gmail_quote" style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;">
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<div class="im"><div><br><br>Dear Mr Tsjerk Wassenaar : </div>
<div>Thank you for your help!</div>
</div><div>I only study on conformation transfromation (transformation) of protein, and need point to corresponding conformation in 2d projection or free energy landscape! I have no any script, please help me! </div>
<div>Best regards!</div>
<div><br><a href="http://cn.webmessenger.yahoo.com/index.php?t=1&to=eWlkPXpoYW94aWl0YzIwMDI-&sig=703fa929658518b2720b087c59cd85f2dabf8844" rel="nofollow" target="_blank"><img src="" alt="4" border="0"></a><br><br>
--- <b>09年12月22日，周二, Tsjerk Wassenaar <i><<a href="mailto:tsjerkw@gmail.com" target="_blank">tsjerkw@gmail.com</a>></i></b> 写道：<br></div>
<blockquote style="border-left: 2px solid rgb(16, 16, 255); padding-left: 5px; margin-left: 5px;"><div class="im"><br>发件人: Tsjerk Wassenaar <<a href="mailto:tsjerkw@gmail.com" target="_blank">tsjerkw@gmail.com</a>><br>
主题: Re: [gmx-users] how to obtain corresponding conformation for each point in the 2-D projection<br>收件人: "Discussion list for GROMACS users" <<a href="mailto:gmx-users@gromacs.org" target="_blank">gmx-users@gromacs.org</a>><br>
</div>日期: 2009年12月22日,周二,下午7:43<div><div></div><div class="h5"><br><br>
<div>Ni hao Xi Zhao,<br><br>Please note again that you're working with projections. There is not necessarily a single conformation that corresponds to the energy minimum from your projection space. <br>You can obtain the minimum from the 2D projection and then find the conformation that yields the projection closest to that point, by taking the Euclidean distance between the projection and the minimum. You'll have to do a bit of scripting there.<br>
<br>Cheers,<br><br><br>Tsjerk<br><br>
<div class="gmail_quote">On Mon, Dec 21, 2009 at 2:51 PM, xi zhao <span dir="ltr"><<a href="http://cn.mc151.mail.yahoo.com/mc/compose?to=zhaoxiitc2002@yahoo.com.cn" rel="nofollow" target="_blank">zhaoxiitc2002@yahoo.com.cn</a>></span> wrote:<br>
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<div>Dear Mr <b>Tsjerk Wassenaar ：</b></div>
<div><b>Thank you for your help! </b></div>
<div><b>what you said is reasonal, but how to </b>implement them, or detial procedure? The 2d projections can convert to a free energy landscape, and how to obtain conformation in the minimum of energy surface?</div>
<div>best regards! <br><br><br><a href="http://cn.webmessenger.yahoo.com/index.php?t=1&to=eWlkPXpoYW94aWl0YzIwMDI-&sig=703fa929658518b2720b087c59cd85f2dabf8844" rel="nofollow" target="_blank"><img src="" alt="4" border="0"></a><br>
<br>--- <b>09年12月21日，周一, Tsjerk Wassenaar <i><<a href="http://cn.mc151.mail.yahoo.com/mc/compose?to=tsjerkw@gmail.com" rel="nofollow" target="_blank">tsjerkw@gmail.com</a>></i></b> 写道：<br></div>
<blockquote style="border-left: 2px solid rgb(16, 16, 255); padding-left: 5px; margin-left: 5px;"><br>发件人: Tsjerk Wassenaar <<a href="http://cn.mc151.mail.yahoo.com/mc/compose?to=tsjerkw@gmail.com" rel="nofollow" target="_blank">tsjerkw@gmail.com</a>><br>
主题: Re: [gmx-users] how to obtain corresponding conformation for each point in the 2-D projection<br>收件人: "Discussion list for GROMACS users" <<a href="http://cn.mc151.mail.yahoo.com/mc/compose?to=gmx-users@gromacs.org" rel="nofollow" target="_blank">gmx-users@gromacs.org</a>><br>
日期: 2009年12月21日,周一,下午7:57
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<div></div>
<div><br><br>
<div>Ni hao,<br><br>Since it's a projection, there is not (in general) a single conformation for each point in the 2D plane. On the other hand, the points you obtained are derived from distinct (ordered) conformations, so it is trivial to retrieve them. Each conformation (time) yields one point: find the time for which the point corresponds with the one your interested in, and extract the conformation from the trajectory.<br>
<br>Cheers,<br><br>Tsjerk<br><br>
<div class="gmail_quote">2009/12/20 xi zhao <span dir="ltr"><<a href="http://cn.mc151.mail.yahoo.com/mc/compose?to=zhaoxiitc2002@yahoo.com.cn" rel="nofollow" target="_blank">zhaoxiitc2002@yahoo.com.cn</a>></span><br>
<blockquote class="gmail_quote" style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;">
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<td style="font-family: inherit; font-size-adjust: inherit; font-stretch: inherit;" valign="top">Dear users for gromacs:<br>We know that observing the sampled conformations in the subspace spanned<br>by the eigenvectors is a so-called two-dimensional projection(2D<br>
projection), in 2-D projection, each point represents a snapshot from<br>the simulation, and the distribution shows the sampled region along the<br>first two eigenvectors during the simulation. But I feel confounded,<br>because I do not know to how to obtain corresponding conformation for<br>
each point in the 2-D projection.Please help me!<br>best regards!<br>thank you!<br><br><br><a href="http://cn.webmessenger.yahoo.com/index.php?t=1&to=eWlkPXpoYW94aWl0YzIwMDI-&sig=703fa929658518b2720b087c59cd85f2dabf8844" rel="nofollow" target="_blank"><img src="" alt="4" border="0"></a></td>
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<hr size="1">
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<br>Computational Chemist<br>Medicinal Chemist<br>Neuropharmacologist<br><br></div><br></div></div>-----下面为附件内容-----<br><br>
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<a href="http://cn.rd.yahoo.com/mail_cn/tagline/card/*http://card.mail.cn.yahoo.com/" rel="nofollow" target="_blank">好玩贺卡等你发，邮箱贺卡全新上线！</a><br>--<br>gmx-users mailing list <a href="http://cn.mc151.mail.yahoo.com/mc/compose?to=gmx-users@gromacs.org" rel="nofollow" target="_blank">gmx-users@gromacs.org</a><br>
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Please don't post (un)subscribe requests to the list. Use the<br>www interface or send it to <a href="http://cn.mc151.mail.yahoo.com/mc/compose?to=gmx-users-request@gromacs.org" rel="nofollow" target="_blank">gmx-users-request@gromacs.org</a>.<br>
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<br>Computational Chemist<br>Medicinal Chemist<br>Neuropharmacologist<br><br></div><br>-----下面为附件内容-----<br><br>
<div>-- <br>gmx-users mailing list <a href="http://cn.mc151.mail.yahoo.com/mc/compose?to=gmx-users@gromacs.org" target="_blank">gmx-users@gromacs.org</a><br><a href="http://lists.gromacs.org/mailman/listinfo/gmx-users" target="_blank">http://lists.gromacs.org/mailman/listinfo/gmx-users</a><br>
Please search the archive at <a href="http://www.gromacs.org/search" target="_blank">http://www.gromacs.org/search</a> before posting!<br>Please don't post (un)subscribe requests to the list. Use the <br>www interface or send it to <a href="http://cn.mc151.mail.yahoo.com/mc/compose?to=gmx-users-request@gromacs.org" target="_blank">gmx-users-request@gromacs.org</a>.<br>
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<hr size="1"><a href="http://cn.rd.yahoo.com/mail_cn/tagline/card/*http://card.mail.cn.yahoo.com/" target="_blank"> 好玩贺卡等你发，邮箱贺卡全新上线！</a><br>--<br>
gmx-users mailing list <a href="mailto:gmx-users@gromacs.org">gmx-users@gromacs.org</a><br>
<a href="http://lists.gromacs.org/mailman/listinfo/gmx-users" target="_blank">http://lists.gromacs.org/mailman/listinfo/gmx-users</a><br>
Please search the archive at <a href="http://www.gromacs.org/search" target="_blank">http://www.gromacs.org/search</a> before posting!<br>
Please don't post (un)subscribe requests to the list. Use the<br>
www interface or send it to <a href="mailto:gmx-users-request@gromacs.org">gmx-users-request@gromacs.org</a>.<br>
Can't post? Read <a href="http://www.gromacs.org/mailing_lists/users.php" target="_blank">http://www.gromacs.org/mailing_lists/users.php</a><br></blockquote></div><br><br clear="all"><br>-- <br>Tsjerk A. Wassenaar, Ph.D.<br>
<br>Computational Chemist<br>Medicinal Chemist<br>Neuropharmacologist<br><br>