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<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D">You need to work out exactly why you have the mis-match, something is screwy.<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D">Something that you are doing does not add up.<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D">What is the charge on the ligand? Appears to be -7.<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D">Why when you add 9 Na+ do you then end up with a charge of +8? Seems that you have actually added 17 sodiums from those numbers.<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size:10.0pt;font-family:"Calibri","sans-serif";color:#1F497D">Catch ya,<br>
<br>
Dr. Dallas Warren<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:10.0pt;font-family:"Calibri","sans-serif";color:#1F497D">Medicinal Chemistry and Drug Action<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:10.0pt;font-family:"Calibri","sans-serif";color:#1F497D">Monash Institute of Pharmaceutical Sciences</span><span style="font-size:10.0pt;font-family:"Calibri","sans-serif";color:#1F497D">, Monash University<br>
381 Royal Parade, Parkville VIC 3010<br>
dallas.warren@monash.edu<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:10.0pt;font-family:"Calibri","sans-serif";color:#1F497D">+61 3 9903 9304<br>
---------------------------------<br>
When the only tool you own is a hammer, every problem begins to resemble a nail.</span><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D">
<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D"><o:p> </o:p></span></p>
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<p class="MsoNormal"><b><span style="font-size:10.0pt;font-family:"Tahoma","sans-serif"">From:</span></b><span style="font-size:10.0pt;font-family:"Tahoma","sans-serif""> gmx-users-bounces@gromacs.org [mailto:gmx-users-bounces@gromacs.org]
<b>On Behalf Of </b>bharat gupta<br>
<b>Sent:</b> Tuesday, 21 June 2011 12:05 PM<br>
<b>To:</b> Discussion list for GROMACS users<br>
<b>Subject:</b> [gmx-users] Re: Increase in charge after adding the ligand<o:p></o:p></span></p>
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<p class="MsoNormal"><o:p> </o:p></p>
<p class="MsoNormal">Hi,<br>
<br>
Initially while preparing the structure , -2 charge was there on the protein. Next, after adding the ligand and executing grompp statement It showing -9.9 charge. So I added 9 sodium ions. but still its showing +8 charge on the system. what shall I do in this
case ??<br clear="all">
<br>
-- <br>
Bharat<br>
Ph.D. Candidate<br>
Room No. : 7202A, 2nd Floor<br>
Biomolecular Engineering Laboratory<br>
Division of Chemical Engineering and Polymer Science<br>
Pusan National University<br>
Busan -609735<br>
South Korea<br>
Lab phone no. - +82-51-510-3680, +82-51-583-8343<o:p></o:p></p>
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<p class="MsoNormal">Mobile no. - 010-5818-3680<br>
E-mail : <a href="mailto:monu46010@yahoo.com" target="_blank">monu46010@yahoo.com</a><o:p></o:p></p>
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<p class="MsoNormal"><o:p> </o:p></p>
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